Welcome to Quizzol's Free Solutions Library!

We're thrilled to have you here! Our ever-growing library is designed to provide you with clear and accurate solutions to help you succeed in your academic journey.

Explore our extensive range of free solutions across various subjects, from mathematics to science, and beyond.

If you need more personalized assistance, we also offer affordable, tailored assignment help. Whether you're facing a challenging problem or need guidance on a project, our dedicated team is here to help you with your homework.

Click Here for Assignment Help

If you appreciate our work, consider supporting us:

Questions and Answers

(159 solutions)

 A 2012 study reported that the opinions of U.S. adults regarding the the issue of abortion has the following distribution:

Legal in all cases

Legal in most cases

Illegal in most cases

Illegal in all cases

Unsure

.23

.31

.23

.16

.07

700 randomly chosen U.S. adults were recently asked about their opinions regarding abortion and the data showed that:

  • 154 responded that abortion should be legal in call cases
  • 252 responded that abortion should be legal in most cases
  • 160 responded that abortion should be illegal in most cases
  • 98 responded that abortion should illegal in all cases
  • 36 were unsure.

We have evidence to conclude that the data do not fit the distribution reported by 2012 study.This is correct. Since the p-value is between 0.01 and 0.02, then p-value < 0.05 and therefore we can reject H0 and conclude that the data do not fit the distribution reported by the 2012 study....

Read More

The chi-square goodness-of-fit test statistic in this case is X2=12.02.

Using the chi-square table (linked hereopens a new window), what can you say about the p-value of the test?

0.01 < p-value < 0.02This is correct. Since there are 5 categories in this case (Legal in all cases, Legal in most cases, Illegal in most cases, Illegal in all cases, Unsure), you need to use row 5-1=4 in the table. As the figure below shows, since the test statistic 12.02 falls between the tw...

Read More

 A 2012 study reported that the opinions of U.S. adults regarding the the issue of abortion has the following distribution:

Legal in all cases

Legal in most cases

Illegal in most cases

Illegal in all cases

Unsure

.23

.31

.23

.16

.07

700 randomly chosen U.S. adults were recently asked about their opinions regarding abortion and the data showed that:

  • 154 responded that abortion should be legal in call cases
  • 252 responded that abortion should be legal in most cases
  • 160 responded that abortion should be illegal in most cases
  • 98 responded that abortion should illegal in all cases
  • 36 were unsure.

We will use the chi-square goodness-of-fit test to assess whether or not the observed data fit the distribution reported by the 2012 study.

If the distribution reported by the 2012 study is still true, how many of the 700 U.S. adults would you expect to respond that abortion should be legal in most case? In other words, what is the expected frequency of U.S. adults who respond that abortion should be legal in most case?

217This is correct. Indeed, the 2012 study claims that 31% of U.S. adults believe that abortion should be legal in most cases. Therefore, if the distribution reported by the 2012 study is still true, we would expect that 31% of the 700 individuals (which is .31*700 = 217) to respond that abortion sh...

Read More

 A 2012 study reported that the opinions of U.S. adults regarding the the issue of abortion has the following distribution:

Legal in all cases

Legal in most cases

Illegal in most cases

Illegal in all cases

Unsure

.23

.31

.23

.16

.07

700 randomly chosen U.S. adults were recently asked about their opinions regarding abortion and the data showed that:

  • 154 responded that abortion should be legal in call cases
  • 252 responded that abortion should be legal in most cases
  • 160 responded that abortion should be illegal in most cases
  • 98 responded that abortion should illegal in all cases
  • 36 were unsure.

We will use the chi-square goodness-of-fit test to assess whether or not the observed data fit the distribution reported by the 2012 study.

Question 1 of 7

Question 1

This is not a form; we suggest that you use the browse mode and read all parts of the question carefully.

Which of the following are the correct null and alternative hypotheses in this case?

H0: The data fit the distribution reported by the 2012 studyHa: The data do not fit the distribution reported by the 2012 study...

Read More

Question 3 of 4

Question 3

This is not a form; we suggest that you use the browse mode and read all parts of the question carefully.

Here are the three sample standard deviations for the verbal reasoning scores for the three groups (secondary school, vocational school, and primary school only):

Column

Std. Dev.

Secundary School

13.994021

Vocational School

14.1778755

Primary School Only

11.713036

Based on this information, do the data meet the condition of equal population standard deviations for the use of the ANOVA?

Yes, because 14.18/11.71 < 2.ExplanationThe condition of equal population standard deviations is considered to be met if the ratio of the largest sample standard deviation to the smallest sample standard deviation is less than 2....

Read More

Please use the following information for Questions 2, 3, and 4.

To determine whether there is a relationship between the type of school attended and verbal reasoning scores for Irish students, three samples with 25 students, in each group, were randomly selected from data used by Raferty and Hout (1985). One group of students attended secondary school, the second group of students attended vocational school, and the third group consisted of students who attended only primary school.

Raftery, A.E. and Hout, M. (1985). Does Irish education approach the meritocratic ideal? A logistic analysis. Economic and Social Review, 16, 115-140.

Question 2 of 4

Question 2

This is not a form; we suggest that you use the browse mode and read all parts of the question carefully.

If we let µ1, µ2, and µbe the mean verbal reasoning scores for students who attended secondary school, vocational school, and primary school only, respectively, the appropriate hypotheses in this case are:

H0: μ1 = μ2 = μ3Ha: μ1, μ2, μ3, are not all equal...

Read More

For which of the following would it be most appropriate to use an ANOVA to analyze the data?

In order to determine the effectiveness of different diet plans, 90 people are randomly assigned to one of three groups: (1) low calorie diet, (2) low-fat diet, or (3) low-carb diet. At the end of 60 days, the number of pounds lost was recorded for each of the participants.ExplanationThere is a cate...

Read More

The analysis was run on the data and the following output was obtained:

ANOVA table


Source

df

SS

MS

F-Stat

P-value

Region

2

18,441

9220.4

17.46

0.000

Error

72

20,594

528.0



Total

74

30,034




Based on this information, we :

Reject the H0 and conclude that the data provide strong evidence that there is a relationship between the region of the world and the quantity of beer that people drink....

Read More

Here are the three sample standard deviations for the beer consumption for the three groups (Asia, Europe and America):


Column

Std. Dev.

Asia

6.5

Europe

7.3

America

5.2

Based on this information, do the data meet the condition of equal population standard deviations for the use of the ANOVA?

Yes, because 7.35.2<27.35.2<2...

Read More

Please use the following information for Questions 2, 3, and 4.

To determine whether there was a relationship between the region of the world that you live in and the amount of beer that you drink, suppose we took 3 samples of 25 people per region from Asia, Europe and America.

Question 2 of 4

Question 2

This is not a form; we suggest that you use the browse mode and read all parts of the question carefully.

If we let µ1, µ2, and µ3 be the average beer per capita in liters for Asia, Europe and America, respectively, the appropriate hypotheses in this case are:

H0: μ1 = μ2 = μ3Ha: μ1, μ2, μ3, are not all equal...

Read More