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ANSWER:
To find Miguel’s salary when he is half a standard deviation below the mean, use the z-score formula in reverse:
X=μ+(z×σ)X = \mu + (z \times \sigma)X=μ+(z×σ)
Where:
μ=80,000\mu = 80{,}000μ=80,000
σ=5,000\sigma = 5{,}000σ=5,000
z=−0.5z = -0.5z=−0.5
X=80,000+(−0.5×5,000)X = 80{,}000 + (-0.5 \times 5{,}000)X=80,000+(−0.5×5,000) X=80,000−2,500X = 80{,}000 - 2{,}500X=80,000−2,500 X=77,500X = 77{,}500X=77,500
✅ Miguel makes $77,500.