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The chi-square goodness-of-fit test statistic in this case is X2=12.02X2=12.02.
Using the chi-square table (linked hereopens a new window), what can you say about the p-value of the test?
0.01 < p-value < 0.02
p-value < 0.01
0.02 < p-value < 0.05
p-value > 0.1
0.05 < p-value < 0.1
ANSWER:
This is correct. Since there are 5 categories in this case (Legal in all cases, Legal in most cases, Illegal in most cases, Illegal in all cases, Unsure), you need to use row 5-1=4 in the table. As the figure below shows, since the test statistic 12.02 falls between the two critical values 11.668 and 13.277, the p-value of the test is between 0.01 and 0.02.
